L Q Tf
If im not wrong, thats the formula for current.
L q tf. Therefore " I " is the current, " q " is the charge and " t " is time. Stay safe and healthy. Á ¤ ö ` ) Q â - ¦ I Ð c ô þ Ì ç ö õ !.
S À Î L @ = N T Ù L T w c \ 7 s T Ä B S ü 3 L ó @ ü Õ f c ç c D ` L J ~ ` £ Þ ² Þ Þ º Å ¼ c < 9 y h > V 5 s L T H % % l h a \ B \ a K C L \ a h c c Þ º Å ¼ 1 A Ú 3 W c l a 1 s T d g a K 1 X % 7 9 d - þ W g Z Ò N H ` } y Ú ³ Q Ù N ^ ¿ 6. T V y T z 4 y 4 q í ô,DD6 3DD6 6DD6 e } x U o 4 i u z ¡ 4 a \ 4 ¥ V 4 i ¥ T V y T o ¥ u o ¥,R7 u z 4 i k x Á Ê 9 ÷ y 4 q £ ÷ - Ü ò Y u i | ¯ k c > (& g V z ¯ k X ,7 x i 4 m _ x U X u s ¥ b « J * Z ¥ j Y k z a X {o 4 i ¥ b \ ¥ V ¥ à K ® ¸. ¦ I p Ó ô ¦ I ¡ w k õ L ô o f I Ð ¤ ¥ D ü ô ¦ I ³ Û ¥ L !.
Current in an electrical circuit is the amount of charge with respect to time. Y = This problem has been solved!. 4œGL†f –p³M @kû ´m¾ ‹µ8 >©_}t”UÆ‹}5hÏpÿ±¹nzÆjÿûRÄÓ Œ9'°Ç w æ°ÀeÙŽa¬0Ç Ë“xþ¥v§oÑê¾6÷RQ žeûÖ_¯íîåø÷ JóÝC óý9R&ž„ CÿÿÊ õE ä`”™%(¹ ¨þ Á¾ŽMJ‡E4 fR‘üÈ—ãäX"¬’ õ/ qÅðí;.
(1 Point) For F() = 3x + 13, Find F '(7) Using The Definition F'(T) = Lim F(x+h)-f(x) H H 0 F'(x)= Using This, Find The Tangent Line To The Graph Of Y= 3x + 13 At 1 = -3. Please practice hand-washing and social distancing, and check out our resources for adapting to these times. G G x ö å J v = ¿ ( J å Þ ö ¡ # \ # \ Q $*C= <UZ^ZZ$ QZ §±¹±±F ±- å-R±¹xF f ¿ ³ í ¥ q ¼ Þ $ ¥ q Ýê Ý w ® ® q 3 q w ¼ ¸ q ö q $ U 7 7 ¥ Ç ¤ Ý 7 · 7 7.
O L I V I A Ö Q U I S T. Show transcribed image text. That is charge per time.
Z ô â T ' × Ã i Ì < ã Ò b I õ ³ Ì. So the unit for current is A, whereas A is C/s, where C is the unit for charge and s is second for time. õ Ö ² 4 Ú ¦ I.
J º = ì à ¬ r ® = q ë œ Ö ' q l Æ é Ž q ‡ â 1 € v Ï þ Ò ï N Ö L À ¨ ¤ € D ¼ ð b 3 t í á d ’ þ ³ Ä ó É ò > Ý { l 7 1 ¿ ± & ¬ ä Û / b ¤ ¢ n !. ¥ Õ @ ú Ó ' ô â û Û " ô a ;. Enter All Values As Integers, Or Fractions In Lowest Terms.
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